4x^2+54x-79=0

Solution for 4x^2+54x-79=0 equation:

4x^2+54x-79=0

a = 4; b = 54; c = -79;
Δ = b2-4ac
Δ = 542-4·4·(-79)
Δ = 4180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4180}=\sqrt{4*1045}=\sqrt{4}*\sqrt{1045}=2\sqrt{1045}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{1045}}{2*4}=\frac{-54-2\sqrt{1045}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{1045}}{2*4}=\frac{-54+2\sqrt{1045}}{8}
$